Ok so lets see... The main "clicks" are as follows:
He-Man
Teela
Man-at-Arms
Sorceress
Orko
Skeletor
Evil-Lyn
Trap Jaw
Merman
Beast-Man
That's 5 on each side. We've already been guaranteed He-Man, Skeletor and Evil-Lyn. So if Evil-Lyn equals fraction of the circumference of Skeletor's base. Then that X's pie is rounded off to the nearest denominator... Then that's multiplied by Orko with Man-at-Arms subtracted from that result...
That means we should DEF be getting at least a Teela next!!! It's almost too easy!!!